1.1.5.b - Circuit 5

Fifth circuit for the myPLTW Digital Electronics class for Activity 1.1.5.b. I(T) = 5.37mA (I(T) = 2.22mA + 600.00μA + 1.82mA + 731.71μA) I(R1) = 2.22mA (I(R1) = 6V / 2700Ω = .00222A, rounded to 2.22mA) I(R2) = 600.00μA (I(R2) = 6V / 10000Ω = .0006A, rounded to 600.00μA) I(R3) = 1.82mA (I(R3) = 6V / 3300Ω = .00182A, rounded to 1.82mA) I(R4) = 731.71μA (I(R4) = 6V / 8200Ω = .00073171A, rounded to 731.71μA) All problems found by using Ohm's Law, I = V / R.