Shering bridge

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Shering bridge

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At balance condition Rx=R2×C1/C3 Rx=5×(10^3)×1×(10^-6)/1×(10^-6)=. 5×10^3 Cx=R1×C3/R2 Cx=2×(10^3)×1×(10^-6)/5×(10^3)= 0.4×(10^-6)=0.4microfarad

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Creator

9001jee

34 Circuits

Date Created

4 years, 2 months ago

Last Modified

4 years, 2 months ago

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