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RC circuit with a Pulse source
Circuit parameter:
Pulse source = 5Vp-p @ 1Hz
R1 = 1kohm
C1 = 100uF
Solve for some capacitor voltages on a given time constant
Equation for discharging capacitor
V(t) = Vmax * e(-t/RC)
if t = RC
V(t) = Vmax * e(-1)
In this circuit
Vmax = 5V
then:
V(t) = 5V * e(-1)
V(t) = 5V * .368
V(t) = 1.84V
if t = RC = 1Kohm x 100 micro Farads
t= .1sec
*note the time value in seconds
Discharging capacitor voltage with respect to time
Run the simulation:
Now look on the graph.
See the Capacitor discharge voltage and note the values at t = RC or .1sec
The time t is the delta value:
t = t2-t1
where:
t = .1sec
What is the Voltage across the capacitor at .1sec?
V(.1sec) = ?
Charging capacitor voltage with respect to time
Equation for charging capacitor
V(t) = Vmax * [1-e(-t/RC)]
if t = RC
V(t) = Vmax * [1-e(-1)]
solve for V(t) where t=RC and Vmax=5V
V(t) = 5V * [1-e(-1)]
V(t) = 5V * [6.3]
V(t) = 3.2V
Run the simulation:
Now look on the graph.
See the Capacitor charging voltage and note the values at t = RC or .1sec
The time t is the delta value:
t = t2-t1
where:
t = .1sec
What is the Voltage across the capacitor at .1sec?
V(.1sec) = ?
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